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Word Break | Dynamic Programming | 1D

Given a string s and a dictionary of strings wordDict, return true if s can be segmented into a space-separated sequence of one or more dictionary words.

Note that the same word in the dictionary may be reused multiple times in the segmentation.

Example 1:

Input: s = "leetcode", wordDict = ["leet","code"]
Output: true
Explanation: Return true because "leetcode" can be segmented as "leet code".

Example 2:

Input: s = "applepenapple", wordDict = ["apple","pen"]
Output: true
Explanation: Return true because "applepenapple" can be segmented as "apple pen apple".
Note that you are allowed to reuse a dictionary word.

Brute Force, Recursive approach

Time complexity is O(n^m), which represents the worst-case scenario when the function has to consider all possible combinations of words to form the input string.

Let’s understand recursive approach,

  • It breaks the given string
  • At each step, we check if we can find a dictionary word that matches the substring. If yes, we move to the next substring and repeat the process until we reach the end of the…

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Sonika | @Walmart | Frontend Developer | 11 Years
Sonika | @Walmart | Frontend Developer | 11 Years

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